What is the derivative of (2^x/(ln(2))) ?

The derivative of (2^x/(ln(2))) is 2^x

What is the first derivative of (2^x/(ln(2))) ?

The first derivative of (2^x/(ln(2))) is 2^x

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\frac{d}{d x} (\frac{2 ^{x}}{ln ( 2 )})

2^{x}

Solution steps

\frac{d}{d x} (\frac{2 ^{x}}{ln ( 2 )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{ln ( 2 )} \frac{d}{d x} (2^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= \frac{1}{ln ( 2 )} \cdot 2^{x} ln (2)

Simplify

\frac{1}{ln ( 2 )} \cdot 2^{x} ln (2) : 2^{x}

= 2^{x}

(2, 3), (1, 3)

n = 6 \sum \infty n^{2} - 16

2 x + y = 4, y = x, y = 0

\int 7 e^{4 x + e^{4 x}} d x

\frac{d}{d s} (\frac{( s - 3 ) ( s - 5 )}{( s + 1 ) ( s + 2 )})

What is the derivative of (2^x/(ln(2))) ?
The derivative of (2^x/(ln(2))) is 2^x
What is the first derivative of (2^x/(ln(2))) ?
The first derivative of (2^x/(ln(2))) is 2^x