What is the solution for (dy)/(dx)=(x^2+y^2)/(yx) ?

The solution for (dy)/(dx)=(x^2+y^2)/(yx) is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}

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(dy)/(dx)=(x^2+y^2)/(yx)

\frac{d y}{d x} = \frac{x ^{2} + y ^{2}}{y x}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

Solution steps

\frac{d y}{d x} = \frac{x ^{2} + y ^{2}}{y x}

Solve Bernoulli ODE:

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

ln (x + 9)

t \to 0 lim (e^{- 3 t})

\frac{3}{s ^{2} - 4}

\frac{d}{d x} (a x^{2} e^{4 x})

y = x, y = \frac{6.75 x}{x ^{2} + 1}

What is the solution for (dy)/(dx)=(x^2+y^2)/(yx) ?
The solution for (dy)/(dx)=(x^2+y^2)/(yx) is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}