What is the limit as x approaches 0+of ln(7/(x^2)) ?

The limit as x approaches 0+of ln(7/(x^2)) is infinity

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limit as x approaches 0+of ln(7/(x^2))

x \to 0 + lim (ln (\frac{7}{x ^{2}}))

\infty

Solution steps

x \to 0 + lim (ln (\frac{7}{x ^{2}}))

Apply the Limit Chain Rule:

\infty

= \infty

n = 1 \sum \infty (\frac{3}{8})^{1 - n}

x \to 1 lim (e^{6 x^{4} - 6 x})

f^{^{'}} (x) = 2^{x}

\int (x^{\frac{2}{3}}) d x

x \to 0 lim (ln (x) x)

What is the limit as x approaches 0+of ln(7/(x^2)) ?
The limit as x approaches 0+of ln(7/(x^2)) is infinity