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Popular >

y'=y^2

Solution

y^{^{'}} = y^{2}

Solution

y = - \frac{1}{t + c _{1}}

Solution steps

y^{'} (t) = y^{2}

Solve separable ODE:

y = - \frac{1}{t + c _{1}}

y = - \frac{1}{t + c _{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y'=y^2 ?
The solution for y'=y^2 is y=-1/(t+c_{1)}