What is the integral from 1 to 4 of (x) ?

The integral from 1 to 4 of (x) is 15/2

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integral from 1 to 4 of (x)

\int_{1}^{4} (x) d x

\frac{15}{2}

Decimal

7.5

Solution steps

\int_{1}^{4} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{1}^{4}

= [\frac{x ^{2}}{2}]_{1}^{4}

Compute the boundaries:

\frac{15}{2}

= \frac{15}{2}

\frac{d ^{3}}{d x ^{3}} (e^{x} cos (x))

\int 9 (ln (x))^{2} d x

\int (1 + cos (x))^{2} d x

\frac{\partial}{\partial x} (cos (2 x) sin (3 y))

f (x) = 2 x^{3} + 3 x^{2} - 12 x + 1

What is the integral from 1 to 4 of (x) ?
The integral from 1 to 4 of (x) is 15/2