What is the tangent of y=sqrt(1+x^3),(2,3) ?

The tangent of y=sqrt(1+x^3),(2,3) is y=2x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=sqrt(1+x^3),(2,3)

tangent of

y = 1 + x^{3}, (2, 3)

y = 2 x - 1

Solution steps

Find the slope of

y = 1 + x^{3} : \frac{d y}{d x} = \frac{3 x ^{2}}{2 1 + x ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(2, 3) : y = 2 x - 1

y = 2 x - 1

\int \frac{1}{( x - 2 ) ln ( x - 2 )} d x

\int (16 x^{3} - 3 x^{2} + 2) d x

x \to 2 lim (\frac{3 x ^{2} + 4 - 4 x ^{2} + 6 x}{x ^{2} - 4})

\int \frac{cos ( x )}{3 + sin ( x )} d x

\int \frac{x ^{3} + 4 x - 2}{( x - 2 ) ( x + 1 )} d x

What is the tangent of y=sqrt(1+x^3),(2,3) ?
The tangent of y=sqrt(1+x^3),(2,3) is y=2x-1