What is (\partial)/(\partial u)(u+uv) ?

The answer to (\partial)/(\partial u)(u+uv) is 1+v

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(\partial)/(\partial u)(u+uv)

\frac{\partial}{\partial u} (u + uv)

1 + v

Solution steps

\frac{\partial}{\partial u} (u + uv)

Treat

v

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial u} (u) + \frac{\partial}{\partial u} (uv)

\frac{\partial}{\partial u} (u) = 1

\frac{\partial}{\partial u} (uv) = v

= 1 + v

(1 + x^{2}) d y = (y - arccot (x)) d x

x \to \frac{1}{2} lim (x sec (π) x)

\int 6 x^{7} d x

\frac{5}{x}, 5 x, 0, 5

\frac{d ^{2}}{d x ^{2}} (4 sin (3 x))

What is (\partial)/(\partial u)(u+uv) ?
The answer to (\partial)/(\partial u)(u+uv) is 1+v