What is the integral of 1-sqrt(x) ?

The integral of 1-sqrt(x) is x-2/3 x^{3/2}+C

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integral of 1-sqrt(x)

\int 1 - x d x

x - \frac{2}{3} x^{\frac{3}{2}} + C

Solution steps

\int 1 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x - \int x d x

\int 1 d x = x

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

= x - \frac{2}{3} x^{\frac{3}{2}}

Add a constant to the solution

= x - \frac{2}{3} x^{\frac{3}{2}} + C

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What is the integral of 1-sqrt(x) ?
The integral of 1-sqrt(x) is x-2/3 x^{3/2}+C