What is the derivative of y=x^{-1} ?

The derivative of y=x^{-1} is -1/(x^2)

What is the first derivative of y=x^{-1} ?

The first derivative of y=x^{-1} is -1/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = x^{- 1}

- \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 1 \cdot x^{- 1 - 1}

Simplify

- 1 \cdot x^{- 1 - 1} : - \frac{1}{x ^{2}}

= - \frac{1}{x ^{2}}

y^{^{'}} = \frac{1}{x y}

f (x) = 8 x^{2} - 3, at x = 3

f (0) = \frac{cos ( x )}{x ^{2} - 1}

\int_{1}^{4} 7 e^{x} d x

n = 1 \sum \infty \frac{2 ^{n}}{1 0 ^{n}}

What is the derivative of y=x^{-1} ?
The derivative of y=x^{-1} is -1/(x^2)
What is the first derivative of y=x^{-1} ?
The first derivative of y=x^{-1} is -1/(x^2)