What is the solution for (dy)/(dx)+2y=3,y(0)=1 ?

The solution for (dy)/(dx)+2y=3,y(0)=1 is y=-(e^{-2x})/2+3/2

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(dy)/(dx)+2y=3,y(0)=1

\frac{d y}{d x} + 2 y = 3, y (0) = 1

y = - \frac{e ^{- 2 x}}{2} + \frac{3}{2}

Solution steps

\frac{d y}{d x} + 2 y = 3

Solve separable ODE:

y = - \frac{e ^{- 2 x}}{2} + \frac{3}{2}

y = - \frac{e ^{- 2 x}}{2} + \frac{3}{2}

f (x) = x^{4} + 8 x

\frac{d}{d x} (\frac{g ( x )}{h ( x )})

f (x) = 4 x - 8

\int 9 x cos (3 x) d x

\int e^{- x} \cdot cos (2 x) d x

What is the solution for (dy)/(dx)+2y=3,y(0)=1 ?
The solution for (dy)/(dx)+2y=3,y(0)=1 is y=-(e^{-2x})/2+3/2