What is the limit as x approaches 5 of sqrt(x^2+4) ?

The limit as x approaches 5 of sqrt(x^2+4) is square root of 29

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 5 of sqrt(x^2+4)

x \to 5 lim (x^{2} + 4)

29

Decimal

5.38516 \dots

Solution steps

x \to 5 lim (x^{2} + 4)

Plug in the value

x = 5

= 5^{2} + 4

Simplify

= 29

\int \frac{3 x ^{2} - 3}{x ^{3} - 3 x} d x

3 x \frac{d y}{d x} + 5 y = 10

\int tan^{6} (9 x) sec^{4} (9 x) d x

\int_{0}^{3} π (2 5 y)^{2} d y

y = F 4 x - x^{2}, (1, 3)

What is the limit as x approaches 5 of sqrt(x^2+4) ?
The limit as x approaches 5 of sqrt(x^2+4) is square root of 29