What is the derivative of asqrt(1+x) ?

The derivative of asqrt(1+x) is a/(2sqrt(1+x))

What is the first derivative of asqrt(1+x) ?

The first derivative of asqrt(1+x) is a/(2sqrt(1+x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (a 1 + x)

\frac{a}{2 1 + x}

Solution steps

\frac{d}{d x} (a 1 + x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= a \frac{d}{d x} (1 + x)

Apply the chain rule:

\frac{1}{2 1 + x} \frac{d}{d x} (1 + x)

= \frac{1}{2 1 + x} \frac{d}{d x} (1 + x)

\frac{d}{d x} (1 + x) = 1

= a \frac{1}{2 1 + x} \cdot 1

Simplify

a \frac{1}{2 1 + x} \cdot 1 : \frac{a}{2 1 + x}

= \frac{a}{2 1 + x}

x + 9, 0.25 x + 9

\frac{d}{d x} (∣ 3 x - 4 ∣)

\int \frac{x ^{2}}{10 - 3 x ^{3}} d x

\int (90 x^{2} sin (2 + 6 x^{3})) d x

\frac{d}{d x} (\frac{3 x + 7}{5 + 2 x})

What is the derivative of asqrt(1+x) ?
The derivative of asqrt(1+x) is a/(2sqrt(1+x))
What is the first derivative of asqrt(1+x) ?
The first derivative of asqrt(1+x) is a/(2sqrt(1+x))