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Popular >

2xdx+dy=0

Solution

2 x d x + d y = 0

Solution

y = - x^{2} + c_{1}

Solution steps

2 x d x + d y = 0

Let

y

be the dependent variable. Divide by

d x

:

2 x + \frac{d y}{d x} = 0

Substitute

\frac{d y}{d x}

with

y^{'} (x)

2 x + y^{^{'}} (x) = 0

Isolate

y^{'} (x) : y^{'} (x) = - 2 x

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - 2 x d x

\int - 2 x d x = - x^{2} + c_{1}

y = - x^{2} + c_{1}

Graph

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\int e^{4 x} d x

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\int \frac{( - 1 ) ^{k}}{( 2 k + 1 ) !} (2 x)^{2 k} d x

\frac{d x}{d t} = x + t

derivative of 3/(sqrt((45+36)^3))derivative of

\frac{3}{( 45 + 36 ) ^{3}}

Frequently Asked Questions (FAQ)

What is the solution for 2xdx+dy=0 ?
The solution for 2xdx+dy=0 is y=-x^2+c_{1}