What is the limit as x approaches pi/2+of 2e^{tan(x)} ?

The limit as x approaches pi/2+of 2e^{tan(x)} is 0

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limit as x approaches pi/2+of 2e^{tan(x)}

x \to \frac{π}{2} + lim (2 e^{t a n (x)})

0

Solution steps

x \to \frac{π}{2} + lim (2 e^{t a n (x)})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 2 \cdot x \to \frac{π}{2} + lim (e^{t a n (x)})

Apply the Limit Chain Rule:

0

= 2 \cdot 0

Simplify

= 0

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\frac{\partial}{\partial x} (- 3 x y ln (x y))

\frac{\partial}{\partial x} (\frac{x y ^{2}}{z ^{3}})

y^{^{''}} = - y

\int x - 7 d x

What is the limit as x approaches pi/2+of 2e^{tan(x)} ?
The limit as x approaches pi/2+of 2e^{tan(x)} is 0