What is (\partial)/(\partial x)(x^2-4y) ?

The answer to (\partial)/(\partial x)(x^2-4y) is 2x

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(\partial)/(\partial x)(x^2-4y)

\frac{\partial}{\partial x} (x^{2} - 4 y)

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} - 4 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (4 y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (4 y) = 0

= 2 x - 0

Simplify

= 2 x

y \frac{d y}{d x} - e^{y^{2}} \cdot x \cdot cos (x) = 0

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\int 4 x^{2} sin (2 x) d x

\frac{\partial}{\partial x} (ln (1 + x^{2} + y^{2} - z^{2}))

\frac{d ^{3} y}{d x ^{3}} - cos (x) = 0

What is (\partial)/(\partial x)(x^2-4y) ?
The answer to (\partial)/(\partial x)(x^2-4y) is 2x