What is the derivative of f(x)=x^n ?

The derivative of f(x)=x^n is nx^{n-1}

What is the first derivative of f(x)=x^n ?

The first derivative of f(x)=x^n is nx^{n-1}

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derivative of

f (x) = x^{n}

n x^{n - 1}

Solution steps

\frac{d}{d x} (x^{n})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= n x^{n - 1}

n = 0 \sum \infty (\frac{1}{2})^{n}

\frac{\partial}{\partial x} (1.2 x^{0.6} y^{0.4})

sin (x - \frac{π}{4})

\int u^{n} d u

\int \frac{5}{x + 2} - \frac{3}{( x + 2 ) ^{2}} d x

What is the derivative of f(x)=x^n ?
The derivative of f(x)=x^n is nx^{n-1}
What is the first derivative of f(x)=x^n ?
The first derivative of f(x)=x^n is nx^{n-1}