What is the derivative of f(x)=2x^2-6x^{1/3} ?

The derivative of f(x)=2x^2-6x^{1/3} is (-2+4x^{5/3})/(x^{2/3)}

What is the first derivative of f(x)=2x^2-6x^{1/3} ?

The first derivative of f(x)=2x^2-6x^{1/3} is (-2+4x^{5/3})/(x^{2/3)}

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derivative of

f (x) = 2 x^{2} - 6 x^{\frac{1}{3}}

\frac{- 2 + 4 x ^{\frac{5}{3}}}{x ^{\frac{2}{3}}}

Solution steps

\frac{d}{d x} (2 x^{2} - 6 x^{\frac{1}{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (6 x^{\frac{1}{3}})

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (6 x^{\frac{1}{3}}) = \frac{2}{x ^{\frac{2}{3}}}

= 4 x - \frac{2}{x ^{\frac{2}{3}}}

Simplify

4 x - \frac{2}{x ^{\frac{2}{3}}} : \frac{- 2 + 4 x ^{\frac{5}{3}}}{x ^{\frac{2}{3}}}

= \frac{- 2 + 4 x ^{\frac{5}{3}}}{x ^{\frac{2}{3}}}

y = 3 x (- x + 1), y = - 3 x

\frac{d}{d x} (e^{m x})

7 + 2 x + x^{3} (5 x^{2} + 1)^{5}

x \to 0 lim (\frac{1}{3 x sin ( x )})

\frac{d}{d x} (ln (\frac{3 x ^{4} + 2}{4 x}))

What is the derivative of f(x)=2x^2-6x^{1/3} ?
The derivative of f(x)=2x^2-6x^{1/3} is (-2+4x^{5/3})/(x^{2/3)}
What is the first derivative of f(x)=2x^2-6x^{1/3} ?
The first derivative of f(x)=2x^2-6x^{1/3} is (-2+4x^{5/3})/(x^{2/3)}