What is the derivative of (2x^2-1+(5x-6)) ?

The derivative of (2x^2-1+(5x-6)) is 4x+5

What is the first derivative of (2x^2-1+(5x-6)) ?

The first derivative of (2x^2-1+(5x-6)) is 4x+5

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\frac{d}{d x} ((2 x^{2} - 1) + (5 x - 6))

4 x + 5

Solution steps

\frac{d}{d x} ((2 x^{2} - 1) + (5 x - 6))

Simplify

(2 x^{2} - 1) + (5 x - 6) : 2 x^{2} + 5 x - 7

= \frac{d}{d x} (2 x^{2} + 5 x - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (5 x) - \frac{d}{d x} (7)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (7) = 0

= 4 x + 5 - 0

Simplify

= 4 x + 5

f (x) = 12 x^{2}

\frac{\partial}{\partial x} (10 x^{\frac{1}{4}} \cdot 2 y^{\frac{3}{4}})

x \to 1 lim (4 x^{2} - 2 x - 6)

\int (1 - x)^{\frac{3}{2}} d x

sec^{5} (x)

What is the derivative of (2x^2-1+(5x-6)) ?
The derivative of (2x^2-1+(5x-6)) is 4x+5
What is the first derivative of (2x^2-1+(5x-6)) ?
The first derivative of (2x^2-1+(5x-6)) is 4x+5