What is the derivative of 6x+29cos((3x/4)+5x^2+3) ?

The derivative of 6x+29cos((3x/4)+5x^2+3) is 10x-87/4 sin((3x)/4)+6

What is the first derivative of 6x+29cos((3x/4)+5x^2+3) ?

The first derivative of 6x+29cos((3x/4)+5x^2+3) is 10x-87/4 sin((3x)/4)+6

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\frac{d}{d x} (6 x + 29 cos (\frac{3 x}{4}) + 5 x^{2} + 3)

10 x - \frac{87}{4} sin (\frac{3 x}{4}) + 6

Solution steps

\frac{d}{d x} (6 x + 29 cos (\frac{3 x}{4}) + 5 x^{2} + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x) + \frac{d}{d x} (29 cos (\frac{3 x}{4})) + \frac{d}{d x} (5 x^{2}) + \frac{d}{d x} (3)

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (29 cos (\frac{3 x}{4})) = - \frac{87}{4} sin (\frac{3 x}{4})

\frac{d}{d x} (5 x^{2}) = 10 x

\frac{d}{d x} (3) = 0

= 6 - \frac{87}{4} sin (\frac{3 x}{4}) + 10 x + 0

Simplify

= 10 x - \frac{87}{4} sin (\frac{3 x}{4}) + 6

\int (2 x - 3)^{5} d x

y \to x lim (\frac{y ^{\frac{2}{3}} - x ^{\frac{2}{3}}}{y - x})

f (x) = x^{2}, at x = 5

\int 1 - cos (4 x) d x

\frac{d}{d x} (1 + x x)

What is the derivative of 6x+29cos((3x/4)+5x^2+3) ?
The derivative of 6x+29cos((3x/4)+5x^2+3) is 10x-87/4 sin((3x)/4)+6
What is the first derivative of 6x+29cos((3x/4)+5x^2+3) ?
The first derivative of 6x+29cos((3x/4)+5x^2+3) is 10x-87/4 sin((3x)/4)+6