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Popular >

derivative of x^3+6x^2+8x-96

Solution

\frac{d}{d x} (x^{3} + 6 x^{2} + 8 x - 96)

Solution

3 x^{2} + 12 x + 8

Solution steps

\frac{d}{d x} (x^{3} + 6 x^{2} + 8 x - 96)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (8 x) - \frac{d}{d x} (96)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (96) = 0

= 3 x^{2} + 12 x + 8 - 0

Simplify

= 3 x^{2} + 12 x + 8

Graph

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Frequently Asked Questions (FAQ)

What is the derivative of x^3+6x^2+8x-96 ?
The derivative of x^3+6x^2+8x-96 is 3x^2+12x+8
What is the first derivative of x^3+6x^2+8x-96 ?
The first derivative of x^3+6x^2+8x-96 is 3x^2+12x+8