What is the integral of (10)/(x^3) ?

The integral of (10)/(x^3) is -5/(x^2)+C

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integral of (10)/(x^3)

\int \frac{10}{x ^{3}} d x

- \frac{5}{x ^{2}} + C

Solution steps

\int \frac{10}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int \frac{1}{x ^{3}} d x

Apply the Power Rule

: - \frac{1}{2 x ^{2}}

= 10 (- \frac{1}{2 x ^{2}})

Simplify

10 (- \frac{1}{2 x ^{2}}) : - \frac{5}{x ^{2}}

= - \frac{5}{x ^{2}}

Add a constant to the solution

= - \frac{5}{x ^{2}} + C

\int \frac{2 x - 1}{x} d x

\int_{0}^{1} 3 x 5^{x} d x

y^{^{''}} + 2 y^{^{'}} - 10 y = 0

\frac{d}{d x} (x^{10} e^{x} csc (x))

x \to 0 lim (7 sin (x) ln (x))