What is the integral from 0 to 24 of sqrt(6x) ?

The integral from 0 to 24 of sqrt(6x) is 192

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 24 of sqrt(6x)

\int_{0}^{24} 6 x d x

192

Solution steps

\int_{0}^{24} 6 x d x

Apply radical rule:

n ab = n a n b,

assuming

a \geq 0, b \geq 0

= \int_{0}^{24} 6 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{0}^{24} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{24}

= 6 [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{24}

Compute the boundaries:

326

= 6 \cdot 326

Simplify

= 192

\frac{d}{d x} (3 x ln (2 x))

f (2.1) = 3 x^{2} - 4 x + 1, (2, 0)

\int cos (x) sin^{3} (x) d x

\frac{e ^{y^{2}}}{( 2 y + 1 ) ^{5}}

\frac{d}{d x} (\frac{2}{3} x^{\frac{3}{2}} - \frac{1}{2} x^{\frac{1}{2}})

What is the integral from 0 to 24 of sqrt(6x) ?
The integral from 0 to 24 of sqrt(6x) is 192