What is the integral of ((1-2x))/(x^2) ?

The integral of ((1-2x))/(x^2) is -(1-2x)/x-2ln|x|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of ((1-2x))/(x^2)

\int \frac{( 1 - 2 x )}{x ^{2}} d x

- \frac{1 - 2 x}{x} - 2 ln ∣ x ∣ + C

Solution steps

\int \frac{1 - 2 x}{x ^{2}} d x

Apply Integration By Parts

: - \frac{1 - 2 x}{x} - \int \frac{2}{x} d x

= - \frac{1 - 2 x}{x} - \int \frac{2}{x} d x

\int \frac{2}{x} d x = 2 ln ∣ x ∣

= - \frac{1 - 2 x}{x} - 2 ln ∣ x ∣

Add a constant to the solution

= - \frac{1 - 2 x}{x} - 2 ln ∣ x ∣ + C

\frac{d}{d x} (\frac{1}{4} e^{- x} + e^{x})

f (x) = x x + 1

x \to 0 lim (\frac{7 ^{x} - 1}{x})

\int \frac{( 5 + x + x )}{x} d x

y^{^{''}} + y = 3 sec^{3} (t)

What is the integral of ((1-2x))/(x^2) ?
The integral of ((1-2x))/(x^2) is -(1-2x)/x-2ln|x|+C