What is the derivative of-1/(x^2-1) ?

The derivative of-1/(x^2-1) is 2/(x^3)

What is the first derivative of-1/(x^2-1) ?

The first derivative of-1/(x^2-1) is 2/(x^3)

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\frac{d}{d x} (- \frac{1}{x ^{2}} - 1)

\frac{2}{x ^{3}}

Solution steps

\frac{d}{d x} (- \frac{1}{x ^{2}} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (\frac{1}{x ^{2}}) - \frac{d}{d x} (1)

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

\frac{d}{d x} (1) = 0

= - (- \frac{2}{x ^{3}}) - 0

Simplify

= \frac{2}{x ^{3}}

\frac{480 x}{( x ^{2} + 5 ) ^{3}}

\frac{d}{d x} (ln (x^{2} - 5))

f (x) = (x^{2} - 8)^{2}

\frac{d}{d x} (x^{2} I n x)

n \to \infty lim (- \frac{1}{n})

What is the derivative of-1/(x^2-1) ?
The derivative of-1/(x^2-1) is 2/(x^3)
What is the first derivative of-1/(x^2-1) ?
The first derivative of-1/(x^2-1) is 2/(x^3)