What is the limit as x approaches 0 of x^7sin(1/x) ?

The limit as x approaches 0 of x^7sin(1/x) is 0

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limit as x approaches 0 of x^7sin(1/x)

x \to 0 lim (x^{7} sin (\frac{1}{x}))

0

Solution steps

x \to 0 lim (x^{7} sin (\frac{1}{x}))

Apply the Squeeze Theorem:

0

= 0

(9 - \frac{x}{9})^{- 7}

x = - 2, x = 1, y = 7 x, y = x^{2} - 8

\frac{d y}{d x}, 6 x^{2} + 3 x y + 2 y^{2} + 17 y - 6 = 0

y^{^{''}} - 7 y^{^{'}} + 12 y = 0

2 x + 1

What is the limit as x approaches 0 of x^7sin(1/x) ?
The limit as x approaches 0 of x^7sin(1/x) is 0