What is the integral of 9θcos(θ) ?

The integral of 9θcos(θ) is 9(θsin(θ)+cos(θ))+C

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integral of 9θcos(θ)

\int 9 θ cos (θ) d θ

9 (θ sin (θ) + cos (θ)) + C

Solution steps

\int 9 θ cos (θ) d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int θ cos (θ) d θ

Apply Integration By Parts

: θ sin (θ) - \int sin (θ) d θ

= 9 (θ sin (θ) - \int sin (θ) d θ)

\int sin (θ) d θ = - cos (θ)

= 9 (θ sin (θ) - (- cos (θ)))

Simplify

= 9 (θ sin (θ) + cos (θ))

Add a constant to the solution

= 9 (θ sin (θ) + cos (θ)) + C

x^{2} - 3, 2 x

e^{x} + 3 x e^{x}

x \to 0 + lim (x^{4 s i n (x)})

y = x^{2} - 9 x, (3, - 18)

\frac{d}{d x} (4 (cos (x^{2}) - 2 x^{2} sin (x^{2})))

What is the integral of 9θcos(θ) ?
The integral of 9θcos(θ) is 9(θsin(θ)+cos(θ))+C