What is (\partial)/(\partial x)(y^2-e^{xy}y) ?

The answer to (\partial)/(\partial x)(y^2-e^{xy}y) is -e^{yx}y^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(y^2-e^{xy}y)

\frac{\partial}{\partial x} (y^{2} - e^{x y} y)

- e^{y x} y^{2}

Solution steps

\frac{\partial}{\partial x} (y^{2} - e^{x y} y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (e^{x y} y)

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (e^{x y} y) = y^{2} e^{y x}

= 0 - y^{2} e^{y x}

Simplify

= - e^{y x} y^{2}

\int (x + 1)^{4} d x

\int \frac{1}{4 x ^{2} - 49} d x

\int 2 cos (4 x) d x

x \to 2 + lim (\frac{2 - x}{x ^{2} - 4})

\frac{d}{d x} (ln (2 x + 4))

What is (\partial)/(\partial x)(y^2-e^{xy}y) ?
The answer to (\partial)/(\partial x)(y^2-e^{xy}y) is -e^{yx}y^2