integral of ln(u)

解答

\int ln (u) d u

u ln (u) - u + C

求解步骤

\int ln (u) d u

使用分布积分法

= u ln (u) - \int 1 d u

\int 1 d u = u

= u ln (u) - u

解答补常数

= u ln (u) - u + C

x \to \infty lim (\frac{x ^{2} + 3}{3 x ^{2} + 1})

\int \frac{2 x ^{3} + x ^{2} - 5}{x - 1} d x

(x^{2} + 1) y^{^{'}} + 5 x (y - 1) = 0, y (0) = 9

n = 0 \sum \infty q^{n}

\int \frac{1 + 8 v}{- 16 v ^{2}} d v