What is implicit (dy)/(dx),x^2+y^2=36 ?

The answer to implicit (dy)/(dx),x^2+y^2=36 is (dy)/(dx)=-x/y

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implicit (dy)/(dx),x^2+y^2=36

implicit derivative

\frac{d y}{d x}, x^{2} + y^{2} = 36

\frac{d y}{d x} = - \frac{x}{y}

Solution steps

x^{2} + y^{2} = 36

Treat

y

y (x)

Differentiate both sides:

2 x + 2 y \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{x}{y}

\frac{d y}{d x} = - \frac{x}{y}

\int (4 x^{3} + x^{2}) (3 x^{4} + x^{3})^{8} d x

\int \frac{1}{z ^{3} z ^{2} - 100} d z

\frac{\partial}{\partial x} (x^{2} y - 3 x y + x y^{2})

\int ln^{2} (x^{2}) d x

\int (2 - \frac{1}{x}) ln (x) d x

What is implicit (dy)/(dx),x^2+y^2=36 ?
The answer to implicit (dy)/(dx),x^2+y^2=36 is (dy)/(dx)=-x/y