What is the tangent of y=9x-6sqrt(x),(1,3) ?

The tangent of y=9x-6sqrt(x),(1,3) is y=6x-3

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tangent of y=9x-6sqrt(x),(1,3)

tangent of

y = 9 x - 6 x, (1, 3)

y = 6 x - 3

Solution steps

Find the slope of

y = 9 x - 6 x : \frac{d y}{d x} = 9 - \frac{3}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(1, 3) : y = 6 x - 3

y = 6 x - 3

x \to 1 lim (x^{4} - 1)

\int \frac{x ^{5} - x ^{4} + 4 x ^{2} - x}{x ^{3} + 1} d x

x \to 0 lim (x cos (\frac{7}{x}))

\frac{x + x}{x ^{2}}

\frac{d}{d x} (ln (4 + x))

What is the tangent of y=9x-6sqrt(x),(1,3) ?
The tangent of y=9x-6sqrt(x),(1,3) is y=6x-3