What is the derivative of f(1)=x^6+4e^x ?

The derivative of f(1)=x^6+4e^x is 6x^5+4e^x

What is the first derivative of f(1)=x^6+4e^x ?

The first derivative of f(1)=x^6+4e^x is 6x^5+4e^x

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derivative of

f (1) = x^{6} + 4 e^{x}

6 x^{5} + 4 e^{x}

Solution steps

\frac{d}{d x} (x^{6} + 4 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{6}) + \frac{d}{d x} (4 e^{x})

\frac{d}{d x} (x^{6}) = 6 x^{5}

\frac{d}{d x} (4 e^{x}) = 4 e^{x}

= 6 x^{5} + 4 e^{x}

\frac{d}{d x} (4 3 x^{5})

\frac{d}{d x} (sin^{2} (cos (2 x)))

\int 2 x^{3} (x^{4} - 3)^{5} d x

\frac{x ^{2}}{x + 9}

\frac{d}{d x} (\frac{x ^{3} - 4 x ^{3}}{2 x})

What is the derivative of f(1)=x^6+4e^x ?
The derivative of f(1)=x^6+4e^x is 6x^5+4e^x
What is the first derivative of f(1)=x^6+4e^x ?
The first derivative of f(1)=x^6+4e^x is 6x^5+4e^x