What is (\partial)/(\partial x)(4x^3-5x^2+8x) ?

The answer to (\partial)/(\partial x)(4x^3-5x^2+8x) is 12x^2-10x+8

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(\partial)/(\partial x)(4x^3-5x^2+8x)

\frac{\partial}{\partial x} (4 x^{3} - 5 x^{2} + 8 x)

12 x^{2} - 10 x + 8

Solution steps

\frac{\partial}{\partial x} (4 x^{3} - 5 x^{2} + 8 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x^{3}) - \frac{\partial}{\partial x} (5 x^{2}) + \frac{\partial}{\partial x} (8 x)

\frac{\partial}{\partial x} (4 x^{3}) = 12 x^{2}

\frac{\partial}{\partial x} (5 x^{2}) = 10 x

\frac{\partial}{\partial x} (8 x) = 8

= 12 x^{2} - 10 x + 8

y^{^{'}} = \frac{2 x + y}{2 x + y + 3}

\int sin^{2} (5 x) d x

\frac{\partial}{\partial x} (5 x^{2} + y^{2})

\frac{d y}{d x} = \frac{y ^{2} - 1}{x ^{2} - 1}, y (5) = 5

What is (\partial)/(\partial x)(4x^3-5x^2+8x) ?
The answer to (\partial)/(\partial x)(4x^3-5x^2+8x) is 12x^2-10x+8