en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+35y=7

Solution

y^{^{'}} + 35 y = 7

Solution

y = - \frac{e ^{- 35 t - c_{1}}}{5} + \frac{1}{5}

Solution steps

y^{'} (t) + 35 y = 7

Solve separable ODE:

y = - \frac{e ^{- 35 t - c_{1}}}{5} + \frac{1}{5}

y = - \frac{e ^{- 35 t - c_{1}}}{5} + \frac{1}{5}

Graph

Popular Examples

derivative of-2t^2-8t+9 derivative of

- 2 t^{2} - 8 t + 9

limit as x approaches 6-of (x-6)/(|x-6|)

x \to 6 - lim (\frac{x - 6}{∣ x - 6 ∣})

derivative of ln(x^x)

\frac{d}{d x} (ln (x^{x}))

integral of 4xe^{-2x^2}

\int 4 x e^{- 2 x^{2}} d x

derivative of (cos(x+2)^3)

\frac{d}{d x} ((cos (x) + 2)^{3})

Frequently Asked Questions (FAQ)

What is the solution for y^'+35y=7 ?
The solution for y^'+35y=7 is y=-(e^{-35t-c_{1}})/5+1/5