What is the tangent of f(x)=3x-cos(x),\at x=0 ?

The tangent of f(x)=3x-cos(x),\at x=0 is y=3x-1

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tangent of f(x)=3x-cos(x),\at x=0

tangent of

f (x) = 3 x - cos (x), at x = 0

y = 3 x - 1

Solution steps

Find the tangent point:

(0, - 1)

Find the slope of

f (x) = 3 x - cos (x) : \frac{df ( x )}{d x} = 3 + sin (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(0, - 1) : y = 3 x - 1

y = 3 x - 1

\int (9 x + 5)^{2} d x

f (x) = x^{- 5}

x^{2} - 8 x + 9

x \to 0 lim (\frac{2 ^{2 x} - 1}{x})

\int ln (z) d z

What is the tangent of f(x)=3x-cos(x),\at x=0 ?
The tangent of f(x)=3x-cos(x),\at x=0 is y=3x-1