What is the derivative of f(-1)=x^2+2-1 ?

The derivative of f(-1)=x^2+2-1 is 2x

What is the first derivative of f(-1)=x^2+2-1 ?

The first derivative of f(-1)=x^2+2-1 is 2x

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derivative of

f (- 1) = x^{2} + 2 - 1

2 x

Solution steps

\frac{d}{d x} (x^{2} + 2 - 1)

Simplify

x^{2} + 2 - 1 : x^{2} + 1

= \frac{d}{d x} (x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= 2 x + 0

Simplify

= 2 x

f (x) = \frac{1}{2 x + 3}

\int (x^{3} + 2 x)^{5} (6 x^{2} + 4) d x

\frac{d}{d x} (ln (\frac{x}{2 e}))

f (x) = x^{2} + 9, (- 2, 13)

\int_{0}^{2} \frac{1}{x - 1} d x

What is the derivative of f(-1)=x^2+2-1 ?
The derivative of f(-1)=x^2+2-1 is 2x
What is the first derivative of f(-1)=x^2+2-1 ?
The first derivative of f(-1)=x^2+2-1 is 2x