What is the limit as x approaches 0 of 1/(1+x^2) ?

The limit as x approaches 0 of 1/(1+x^2) is 1

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limit as x approaches 0 of 1/(1+x^2)

x \to 0 lim (\frac{1}{1 + x ^{2}})

1

Solution steps

x \to 0 lim (\frac{1}{1 + x ^{2}})

Plug in the value

x = 0

= \frac{1}{1 + 0 ^{2}}

Simplify

= 1

\frac{d}{d x} ((x^{- 2} + x)^{3} (4 x)^{- 2 x})

x y^{^{'}} = 4 x^{4} cos (2 x) + 3 y

x \to 0 lim (x sin (\frac{π}{x}))

y = 5 x - x^{2}, y = 2 x, (3, 6)

\frac{\partial}{\partial x} (4 y - 3 x^{2})

What is the limit as x approaches 0 of 1/(1+x^2) ?
The limit as x approaches 0 of 1/(1+x^2) is 1