What is the integral from-1 to 0 of 1/(x^2) ?

The integral from-1 to 0 of 1/(x^2) is diverges

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integral from-1 to 0 of 1/(x^2)

\int_{- 1}^{0} \frac{1}{x ^{2}} d x

diverges

Solution steps

\int_{- 1}^{0} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{- 1}^{0}

= [- \frac{1}{x}]_{- 1}^{0}

Compute the boundaries:

diverges

= diverges

\frac{4 s e ^{- 4 s}}{2 s ^{2} + 50}

\frac{s + 1}{s ^{2} + s + 1}

\frac{d}{d t} (ln (sec (t) + tan (t)))

y^{^{'}} = y (2 x - 5)

\int 24 (1 - x)^{5} d x

What is the integral from-1 to 0 of 1/(x^2) ?
The integral from-1 to 0 of 1/(x^2) is diverges