What is the derivative of ln(x^2+7) ?

The derivative of ln(x^2+7) is (2x)/(x^2+7)

What is the first derivative of ln(x^2+7) ?

The first derivative of ln(x^2+7) is (2x)/(x^2+7)

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\frac{d}{d x} (ln (x^{2} + 7))

\frac{2 x}{x ^{2} + 7}

Solution steps

\frac{d}{d x} (ln (x^{2} + 7))

Apply the chain rule:

\frac{1}{x ^{2} + 7} \frac{d}{d x} (x^{2} + 7)

= \frac{1}{x ^{2} + 7} \frac{d}{d x} (x^{2} + 7)

\frac{d}{d x} (x^{2} + 7) = 2 x

= \frac{1}{x ^{2} + 7} \cdot 2 x

Simplify

\frac{1}{x ^{2} + 7} \cdot 2 x : \frac{2 x}{x ^{2} + 7}

= \frac{2 x}{x ^{2} + 7}

(x^{- 1})^{^{'}}

(x - 1)^{2} (x - 1.05)^{2}

\int \frac{x}{x ^{2} - 7 x + 12} d x

x \to \frac{1}{2} lim (- 4 x + 2)

\frac{d}{d x} (3 x - x^{2})

What is the derivative of ln(x^2+7) ?
The derivative of ln(x^2+7) is (2x)/(x^2+7)
What is the first derivative of ln(x^2+7) ?
The first derivative of ln(x^2+7) is (2x)/(x^2+7)