What is laplacetransform 5(t-4) ?

The answer to laplacetransform 5(t-4) is 5/(s^2)-(20)/s

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laplacetransform 5(t-4)

laplace transform

5 (t - 4)

\frac{5}{s ^{2}} - \frac{20}{s}

Solution steps

L {5 (t - 4)}

Expand

5 (t - 4) : 5 t - 20

= L {5 t - 20}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= 5 L {t} - L {20}

L {t} : \frac{1}{s ^{2}}

L {20} : \frac{20}{s}

= 5 \cdot \frac{1}{s ^{2}} - \frac{20}{s}

Refine

5 \frac{1}{s ^{2}} - \frac{20}{s} : \frac{5}{s ^{2}} - \frac{20}{s}

= \frac{5}{s ^{2}} - \frac{20}{s}

\int \frac{x ^{2} + 2 + x}{3 2 + x} d x

x^{2} \cdot 2

x \to \infty lim (- 2 e^{- x} + 2)

\int 3 x y d y

\frac{d y}{d x}, y = (sin (x))^{6 x}

What is laplacetransform 5(t-4) ?
The answer to laplacetransform 5(t-4) is 5/(s^2)-(20)/s