What is the sum from n=0 to infinity of (n+1)/3 ?

The sum from n=0 to infinity of (n+1)/3 is diverges

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sum from n=0 to infinity of (n+1)/3

n = 0 \sum \infty \frac{n + 1}{3}

diverges

Solution steps

n = 0 \sum \infty \frac{n + 1}{3}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= \frac{1}{3} \cdot n = 0 \sum \infty n + 1

Apply Series Divergence Test:

diverges

= \frac{1}{3} diverges

= diverges

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What is the sum from n=0 to infinity of (n+1)/3 ?
The sum from n=0 to infinity of (n+1)/3 is diverges