What is the integral of arccos(7x) ?

The integral of arccos(7x) is xarccos(7x)-1/7 sqrt(1-49x^2)+C

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integral of arccos(7x)

\int arccos (7 x) d x

x arccos (7 x) - \frac{1}{7} 1 - 49 x^{2} + C

Solution steps

\int arccos (7 x) d x

Apply Integration By Parts

: x arccos (7 x) - \int - \frac{7 x}{1 - 49 x ^{2}} d x

= x arccos (7 x) - \int - \frac{7 x}{1 - 49 x ^{2}} d x

\int - \frac{7 x}{1 - 49 x ^{2}} d x = \frac{1}{7} 1 - 49 x^{2}

= x arccos (7 x) - \frac{1}{7} 1 - 49 x^{2}

Add a constant to the solution

= x arccos (7 x) - \frac{1}{7} 1 - 49 x^{2} + C

n = 0 \sum \infty n + 2

\frac{d x}{d t} = - 2 x - 3 x^{2}

(cos^{2} (s) - 4 s^{2})^{2}

\int e^{4 x} cos (9 x) d x

\int_{- 2 π}^{2 π} (sin^{2} (x) + 1) d x

What is the integral of arccos(7x) ?
The integral of arccos(7x) is xarccos(7x)-1/7 sqrt(1-49x^2)+C