What is the derivative of f(x)=8-x^2 ?

The derivative of f(x)=8-x^2 is -2x

What is the first derivative of f(x)=8-x^2 ?

The first derivative of f(x)=8-x^2 is -2x

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derivative of

f (x) = 8 - x^{2}

- 2 x

Solution steps

\frac{d}{d x} (8 - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (8) = 0

\frac{d}{d x} (x^{2}) = 2 x

= 0 - 2 x

Simplify

= - 2 x

\int u^{1} d u

y^{(\frac{1}{2})} \frac{d y}{d x} + y^{(\frac{3}{2})} = 1, y (0) = 9

f (x) = cos (x) - 1

\frac{d}{d x} (e^{2 x})

\int \frac{y}{( y + 2 ) ( 5 y - 1 )} d y

What is the derivative of f(x)=8-x^2 ?
The derivative of f(x)=8-x^2 is -2x
What is the first derivative of f(x)=8-x^2 ?
The first derivative of f(x)=8-x^2 is -2x