What is the integral of 1/(sqrt(1-y^2)) ?

The integral of 1/(sqrt(1-y^2)) is arcsin(y)+C

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integral of 1/(sqrt(1-y^2))

\int \frac{1}{1 - y ^{2}} d y

arcsin (y) + C

Solution steps

\int \frac{1}{1 - y ^{2}} d y

Use the common integral:

\int \frac{1}{1 - y ^{2}} d y = arcsin (y)

= arcsin (y)

Add a constant to the solution

= arcsin (y) + C

f (x) = x^{4 x}

e^{- 3 x} + e^{2 x}

\int \frac{8 - 128 x}{49 - 64 x ^{2}} d x

\frac{\partial}{\partial x} (3 x^{3} + 4 x^{2} y - 3 y^{3})

x \to 0 lim (\frac{3 8 + x - 3 8}{x})

What is the integral of 1/(sqrt(1-y^2)) ?
The integral of 1/(sqrt(1-y^2)) is arcsin(y)+C