What is the derivative of 9x^3-7x ?

The derivative of 9x^3-7x is 27x^2-7

What is the first derivative of 9x^3-7x ?

The first derivative of 9x^3-7x is 27x^2-7

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\frac{d}{d x} (9 x^{3} - 7 x)

27 x^{2} - 7

Solution steps

\frac{d}{d x} (9 x^{3} - 7 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x^{3}) - \frac{d}{d x} (7 x)

\frac{d}{d x} (9 x^{3}) = 27 x^{2}

\frac{d}{d x} (7 x) = 7

= 27 x^{2} - 7

\frac{d}{d x} ((x^{3} + 3)^{5})

\int \frac{1}{( x + 4 ) x ^{2} + 8 x + 12} d x

\frac{d}{d x} (\frac{x ^{4}}{2})

\int_{- 1}^{4} (x + 3) d x

\frac{d}{d x} (- 7 e^{x})

What is the derivative of 9x^3-7x ?
The derivative of 9x^3-7x is 27x^2-7
What is the first derivative of 9x^3-7x ?
The first derivative of 9x^3-7x is 27x^2-7