What is the integral from 0 to infinity of e^{-y} ?

The integral from 0 to infinity of e^{-y} is 1

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integral from 0 to infinity of e^{-y}

\int_{0}^{\infty} e^{- y} d y

1

Solution steps

\int_{0}^{\infty} e^{- y} d y

Compute the indefinite integral:

\int e^{- y} d y = - e^{- y} + C

Compute the boundaries:

\int_{0}^{\infty} e^{- y} d y = 0 - (- 1)

= 0 - (- 1)

Simplify

= 1

\int 7 x + 8 y^{2} d x

\int \frac{1}{( x - 5 ) ^{2} ( x + 3 )} d x

x \frac{d y}{d x} + y = 4 x + 1

f (x) = \frac{3}{x}, at x = 3

\frac{d}{d x} (\frac{3 x - 3}{2 x})

What is the integral from 0 to infinity of e^{-y} ?
The integral from 0 to infinity of e^{-y} is 1