What is the derivative of f(x)=x^2-3x ?

The derivative of f(x)=x^2-3x is 2x-3

What is the first derivative of f(x)=x^2-3x ?

The first derivative of f(x)=x^2-3x is 2x-3

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derivative of

f (x) = x^{2} - 3 x

2 x - 3

Solution steps

\frac{d}{d x} (x^{2} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

= 2 x - 3

\frac{1}{3 + 2 x}

\frac{1}{1 - x}, 0

x \to 0 + lim (ln^{2} (x))

x \to 2 lim (\frac{x + 6}{x ^{2}})

x \to 0.9 lim (x^{2} + 3 x + 2)

What is the derivative of f(x)=x^2-3x ?
The derivative of f(x)=x^2-3x is 2x-3
What is the first derivative of f(x)=x^2-3x ?
The first derivative of f(x)=x^2-3x is 2x-3