What is the derivative of 4x^3-46x^2+120x ?

The derivative of 4x^3-46x^2+120x is 12x^2-92x+120

What is the first derivative of 4x^3-46x^2+120x ?

The first derivative of 4x^3-46x^2+120x is 12x^2-92x+120

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\frac{d}{d x} (4 x^{3} - 46 x^{2} + 120 x)

12 x^{2} - 92 x + 120

Solution steps

\frac{d}{d x} (4 x^{3} - 46 x^{2} + 120 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (46 x^{2}) + \frac{d}{d x} (120 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (46 x^{2}) = 92 x

\frac{d}{d x} (120 x) = 120

= 12 x^{2} - 92 x + 120

\int \frac{1}{x} d x

\int sin (5 x) cos (x) d x

\int \frac{x ^{3} - x ^{2} + 2 x - 6}{x} d x

4 x + 7, 2 x + 29, 6, 16

x \to - 4 lim ((1 - x)^{3})

What is the derivative of 4x^3-46x^2+120x ?
The derivative of 4x^3-46x^2+120x is 12x^2-92x+120
What is the first derivative of 4x^3-46x^2+120x ?
The first derivative of 4x^3-46x^2+120x is 12x^2-92x+120