What is the derivative of y=(x^4+1)^4 ?

The derivative of y=(x^4+1)^4 is 16x^3(x^4+1)^3

What is the first derivative of y=(x^4+1)^4 ?

The first derivative of y=(x^4+1)^4 is 16x^3(x^4+1)^3

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derivative of

y = (x^{4} + 1)^{4}

16 x^{3} (x^{4} + 1)^{3}

Solution steps

\frac{d}{d x} ((x^{4} + 1)^{4})

Apply the chain rule:

4 (x^{4} + 1)^{3} \frac{d}{d x} (x^{4} + 1)

= 4 (x^{4} + 1)^{3} \frac{d}{d x} (x^{4} + 1)

\frac{d}{d x} (x^{4} + 1) = 4 x^{3}

= 4 (x^{4} + 1)^{3} \cdot 4 x^{3}

Simplify

= 16 x^{3} (x^{4} + 1)^{3}

\int \frac{1}{x ^{2} + 11 x + 28} d x

y^{^{'}} = 5 x^{4} e^{- x^{5}} + e^{x}

n = 0 \sum \infty n! 2^{n} n^{- n}

f (x) = 2 x^{3} + 3 x^{2} - 12 x + 8

y = \frac{x ^{x}}{sin ( x )}

What is the derivative of y=(x^4+1)^4 ?
The derivative of y=(x^4+1)^4 is 16x^3(x^4+1)^3
What is the first derivative of y=(x^4+1)^4 ?
The first derivative of y=(x^4+1)^4 is 16x^3(x^4+1)^3