What is the limit as x approaches 2 of (x^3+8)/(x-2) ?

The limit as x approaches 2 of (x^3+8)/(x-2) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 2 of (x^3+8)/(x-2)

x \to 2 lim (\frac{x ^{3} + 8}{x - 2})

diverges

Solution steps

x \to 2 lim (\frac{x ^{3} + 8}{x - 2})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 2 + lim (\frac{x ^{3} + 8}{x - 2}) = \infty

x \to 2 - lim (\frac{x ^{3} + 8}{x - 2}) = - \infty

= diverges

\frac{\partial}{\partial y} (e^{x - 1} cos (y))

\frac{\partial}{\partial x} (72 y^{7} x^{7} - 56 y^{6} x^{6})

\frac{1 - x}{1 + x}

x \to 0 lim (\frac{5 x + 6}{x})

x \to 3 + lim (\frac{x ^{2}}{9 - x ^{2}})

What is the limit as x approaches 2 of (x^3+8)/(x-2) ?
The limit as x approaches 2 of (x^3+8)/(x-2) is diverges