What is the integral of (1/(x^3)+7/(x^2)) ?

The integral of (1/(x^3)+7/(x^2)) is -1/(2x^2)-7/x+C

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integral of (1/(x^3)+7/(x^2))

\int (\frac{1}{x ^{3}} + \frac{7}{x ^{2}}) d x

- \frac{1}{2 x ^{2}} - \frac{7}{x} + C

Solution steps

\int \frac{1}{x ^{3}} + \frac{7}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x ^{3}} d x + \int \frac{7}{x ^{2}} d x

\int \frac{1}{x ^{3}} d x = - \frac{1}{2 x ^{2}}

\int \frac{7}{x ^{2}} d x = - \frac{7}{x}

= - \frac{1}{2 x ^{2}} - \frac{7}{x}

Add a constant to the solution

= - \frac{1}{2 x ^{2}} - \frac{7}{x} + C

f (x) = x^{2} + 5, (2, 9)

10 1 + x

\int \frac{1}{x ^{2} ( 1 - x )} d x

\frac{\partial}{\partial t} (e^{- 7 t} cos (π x))

x \to \frac{π}{4} lim (\frac{sin ( x - \frac{π}{4} )}{4 x - π})

What is the integral of (1/(x^3)+7/(x^2)) ?
The integral of (1/(x^3)+7/(x^2)) is -1/(2x^2)-7/x+C